Lecture
Mediaspace scheduled maintenance: Aug 25, 2026 07:00 - 12:00 AM. During this time, videos will be temporarily unavailable. Check status updates.
This lecture presents the solution to exercise 12, focusing on finding the values of C for which -1 is an eigenvalue of a parameterized 3 by 3 matrix. The instructor explains the logic behind determining the eigenvalue and demonstrates the algebraic steps to solve for the determinant of the matrix. By carefully working through the calculations, it is shown that the value of C needs to be -2 for -1 to be an eigenvalue of the matrix.
This video is available exclusively on Mediaspace for a restricted audience. Please log in to MediaSpace to access it if you have the necessary permissions.
Watch on Mediaspace